array of pointers.

#include <stdio.h>

int main(void)
{
float *ap[5], n1, n2, n3, n4, n5;
int x;

ap[0] = &n1;
ap[1] = &n2;
ap[2] = &n3;
ap[3] = &n4;
ap[4] = &n5;

for(x = 0 ; x < 5 ; x++)
{
*ap[x] = (x + 1) / 10.0;
}

printf("\n%f\t%f\t%f\t%f\t%f", n1, n2, n3, n4, n5);

return 0;
}

No comments:

Post a Comment

kiss on google ads if you are anonymous because your ip is trackable.thank you.

......from.admin