Write a general-purpose function to convert any given year into its roman equivalent. The following table shows the roman equivalents of decimal numbers: Decimal:........Roman 1.....................i 5....................v 10..................x 50..................l 100................c 500...............d 1000.............m Example: Roman equivalent of 1988 is mdcccclxxxviii Roman equivalent of 1525 is mdxxv

This program is a big lengthy owing to the use of Case Statements. This program can also be rewritten using Arrays, which will reduce the length considerably.


#include<stdio.h>
main()
{

int year;
int convert (int year);



{

printf("Note:Enter a four year digit year.\n\n");

printf("Enter the year that you wanna convert to Roman: " );

scanf ("%d", &year);

if (year> 1999)

{
printf("Invalid Year.Please enter again.\n\n");
}
}

convert(year);


}



convert(int year)

{
int i;

printf("\nYear converted to Roman:");


i=(year/1000); //thousands place
if(i==1)

{
printf("m");
}


i=((year/100)%10); //hundreds place

switch (i)
{
case 1:
printf("c");

break;

case 2:
printf("cc");

break;

case 3:
printf("ccc");

break;

case 4:
printf("cd");

break;

case 5:
printf("d");

break;

case 6:
printf("dc");

break;

case 7:
printf("dcc");

break;

case 8:
printf("dccc");

break;

case 9:
printf("dcccc"); //this part you may think is wrong..9 -> cm

break; //but i have taken a hint from the example in the question.

}



i=((year/10)%10); //tens place

switch(i)
{
case 1:
printf("x");

break;

case 2:
printf("xx");

break;

case 3:
printf("xxx");

break;

case 4:
printf("xl");

break;

case 5:
printf("l");

break;

case 6:
printf("lx");

break;

case 7:
printf("lxx");

break;

case 8:
printf("lxxx");

break;

case 9:
printf("lxxxx"); //had it not been for this example, it would have been xc

break;

}



i=year%10; //ones place

switch(i)
{
case 1:
printf("i");

break;

case 2:
printf("ii");

break;

case 3:
printf("iii");

break;

case 4:
printf("iv");

break;

case 5:
printf("v");

break;

case 6:
printf("vi");

break;

case 7:
printf("vii");

break;

case 8:
printf("viii");

break;

case 9:
printf("ix");

break;
}


printf ("\n\n");

return 0;

}







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